3x^2+7x-88=5

Solution for 3x^2+7x-88=5 equation:

3x^2+7x-88=5

We move all terms to the left:

3x^2+7x-88-(5)=0

We add all the numbers together, and all the variables

3x^2+7x-93=0

a = 3; b = 7; c = -93;
Δ = b2-4ac
Δ = 72-4·3·(-93)
Δ = 1165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1165}}{2*3}=\frac{-7-\sqrt{1165}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1165}}{2*3}=\frac{-7+\sqrt{1165}}{6}
$